SELINA Solutions for Class 10 Chemistry Chapter 11 - Study of Compounds D. Sulphuric Acid

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Chapter 11 - Study of Compounds D. Sulphuric Acid Exercise Intext 1

Question 1

Comment, sulphuric acid is referred to as

(a) King of chemicals

(b) Oil of vitriol

Solution 1

(a) Sulphuric acid is called King of Chemicals because there is no other manufactured compound which is used by such a large number of key industries.

(b) Sulphuric acid is referred to as Oil of vitriol as it was obtained as an oily viscous liquid by heating crystals of green vitriol.

Question 2

Sulphuric acid is manufactured by contact process

(a) Give two balanced equations to obtain SO2 in this process.

(b) Give the conditions for the oxidation of SO2

(c) Name the catalyst used.

(d) Why H2SO4 is not obtained by directly reacting SO3 with water.

(e) Name the chemical used to dissolve SO3 and also name the product formed.

(f) Name a gas that can be oxidized to sulphur.

Solution 2

(a) Two balanced equations to obtain SO2 is:

(i) 4FeS2 + 11O2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid2Fe2O3 +8SO2

(ii) S +O2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidSO2

(b) The conditions for the oxidation of SO2 are:

(i) The temperature should be as low as possible. The yield has been found to be maximum at about 4100C-450oC

(ii) High pressure (2 atm) is favoured because the product formed has less volume than reactant.

(iii) Excess of oxygen increases the production of sulphur trioxide.

(iv) Vanadium pentoxide or platinised asbestos is used as catalyst.

(c) Vanadium pentoxide (V2O5)

(d) Sulphuric acid is not obtained directly by reacting SO3 with water because the reaction is highly exothermic which produce the fine misty droplets of sulphuric acid that is not directly absorbed by water.

(e)The chemical used to dissolve SO3 is concentrated sulphuric acid. The product formed is oleum.

(f) Hydrogen sulphide.

Question 3

Why the impurity of arsenic oxide must be removed before passing the mixture of SO2 and air through the catalytic chamber?

Solution 3

Impurity of ARSENIC poisons the catalyst [i.e. deactivates the catalyst]. So, it must be removed before passing the mixture of SO2 air through the catalytic chamber.

Question 4

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

 

(a) Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.

(b) In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two -steps procedure is used. Write the equations for the two steps involved in D.

(c) What type of substance will liberate sulphur dioxide from sodium sulphite in step E?

(d) Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.

Solution 4

(a) The catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C is Vanadium pentoxide.

(b) The two steps for the conversion of sulphur trioxide to sulphuric acid is:

(i) SO3 + H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidH2S2O7

(ii) H2S2O7 + H2O Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid2H2SO4

(c)The substance that will liberate sulphur dioxide in step E is dilute H2SO4.

(d) The equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F is:

SO2+2NaOHSelina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO3+H2O

         Or

Na2O+SO2Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO3

Chapter 11 - Study of Compounds D. Sulphuric Acid Exercise Ex. 11

Question 1

Why is water not added to concentrated H2SO4 in order to dilute it?

Solution 1

Water is not added to concentrated acid since it is an exothermic reaction. If water is added to the acid, there is a sudden increase in temperature and the acid being in bulk tends to spurt out with serious consequences.

Question 2

Give two balanced reactions of each type to show the following properties of sulphuric acid.

(a) Acidic nature

(b) Oxidising agent

(d) Non-volatile nature

Solution 2

Balanced reactions are:

(a) Acidic nature:

(i) Dilute H2SO4 reacts with basic oxides to form sulphate and water.

2 NaOH+H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4+2H2O

(ii) CuO+H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCuSO4+H2O

(iii) It reacts with carbonate to produce CO2.

Na2CO3+H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4+H2O+CO2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

(b) Oxidising agent:

H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidH2O +SO2 +[O]

Nascent oxygen oxidizes non-metals, metals and inorganic compounds.

For example,

Carbon to carbon dioxide

C+H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCO2 +H2O +2SO2

Sulphur to sulphur dioxide

S +H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid3SO2 +2H2O

(d) Non-volatile nature:

It has a high boiling point (356oC) so it is considered to be non-volatile. Therefore, it is used for preparing volatile acids like hydrochloric acid, nitric acid from their salts by double decomposition reaction.

NaCl + H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 +HCl

KCl + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidKHSO4 +HCl

Question 3

Give a chemical test to distinguish between:

(a) Dilute sulphuric acid and dilute hydrochloric acid

(b) Dilute sulphuric acid and conc.sulphuric acid

Solution 3

(a)Bring a glass rod dipped in Ammonia solution near the mouth of each test tubes containing dil. Hel and dil. H2SO4each.

Dil HCl

Dil. H2SO4

White fumes of ammonium chloride

No such fumes

 

(b)

1. Dilute sulphuric acid treated with zinc gives Hydrogen gas which bums with pop sound.

Concentrated H2SO4 gives SO2 gas with zinc and the gas turns Acidified potassium dichromate paper green.

2.Barium chloride solution gives white ppt. with dilute H2SO4, This white ppt. is insoluble in all acids.

Concentrated H2SO4 and NaCl mixture when heated gives dense white fumes if glass rod dipped in Ammonia solution is brought near it.

Question 4

Name the products formed when hot and concentrated sulphuric acid reacts with the following:

(a) Sulphur

(b) NaOH

(c) Sugar

(d) Carbon

(e) Copper

Solution 4

(a) When sulphuric acid reacts with sulphur the product formed is Sulphur dioxide is formed.

S +2H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid3SO2 + 2H2O

(b) When sulphuric acid reacts with sodium hydroxide it neutralizes base to form sodium sulphate.

2NaOH + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4 + 2H2O

(c) When sulphuric acid reacts with sugar it forms carbon

C12 H22O11Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid12C + 11H2O

(d) When sulphuric acid reacts with carbon it forms carbon dioxide and sulphur dioxide gas.

C +2H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCO2 + 2H2O + 2SO2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

(e) When sulphuric acid reacts with copper it forms copper sulphate and sulphur dioxide.

Cu + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCuSO4 + 2H2O + SO2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

Question 5

Why is:

(a) Concentrated sulphuric acid kept in air tight bottles?

(b) H2SO4 is not a drying agent for H2S?

(c) Sulphuric acid used in the preparation of HCl and HNO3? Give equation in both cases.

Solution 5

(a) Concentrated sulphuric acid is hygroscopic substance that absorbs moisture when exposed to air. Hence, it is stored in air tight bottles.

(b) Sulphuric acid is not a drying agent for H2S because it reacts with H2S to form sulphur.

H2SO4+H2S Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid2H2O+SO2+S Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

(c) Concentrated sulphuric acid has high boiling point (356oC). So, it is considered to be non-volatile. Hence, it is used for preparing volatile acids like Hydrochloric acid and Nitric acids from their salts by double decomposition.

NaCl+H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 +HCl

NaNO3 +H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 +HNO3

Question 6

What property of conc. H2SO4 is made use of in each of the following cases? Give an equation for the reaction in each case

(a) In the production of HCl gas when it reacts with a chlorine

(b) In the preparation of CO from HCOOH

(c) As a source of hydrogen by diluting it and adding a strip of magnesium

(d) In the preparation of sulphur dioxide by warming a mixture of conc. Sulphuric acid and copper -turnings.

(e) Hydrogen sulphide gas is passed through concentrated sulphuric acid

(f) Its reaction with (i) ethanol (ii) carbon

Solution 6

(a) Due to its reducing property. i.e, it is a non-volatile acid.

NaCl+ H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 + HCl

(Conc.)

(b) It is a dehydrating agent.

HCOOH Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCO + H2O

(c) Magnesium is present above hydrogen in the reactivity series so sulphuric acid is able to liberate hydrogen gas by reacting with magnesium strip.

Mg + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidMgSO4+H2

(d) Due to its oxidizing character

Cu +H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCuSO4 +2H2O +SO2

(e) Due to its oxidizing property Hydrogen sulphide gas is passed through concentrated sulphuric acid to liberate sulphur dioxide and sulphur is formed.

H2S + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidS + 2H2O + SO2

(f) 

(i) Ethanol

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

(ii) Carbon

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

Question 7

What is the name given to the salts of:

(a) Sulphurous acid

(b) Sulphuric acid

Solution 7

The name of the salt of

(a) Hydrogen sulphites and Sulphites.

(b) Sulphate and bisulphate.

Question 8

Give reasons for the following.

(a) Sulphuric acid forms two types of salts with NaOH

(b) Red brown vapours are produced when concentrated sulphuric acid is added to hydrogen bromide.

(c) A piece of wood becomes black when concentrated sulphuric acid is poured on it

(d) Brisk effervescence is seen when oil of vitriol is added to sodium carbonate.

Solution 8

(a) Two types of salts are formed when sulphuric acid reacts with NaOH because sulphuric acid is dibasic.

NaOH + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 + H2O

2NaOH + H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4 + 2H2O

(b) When hydrogen bromide reacts with sulphuric acid the bromine gas is obtained which produce red brown vapours.

2KBr+3H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid2KHSO4+SO2+Br2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid+2H2O

(c) A piece of wood becomes black when concentrated sulphuric acid is poured on it because it gives a mass of carbon.

(d) When sulphuric acid is added to sodium carbonate it liberates carbon dioxide which produces brisk effervescence.

Na2CO3+H2SO4Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidSelina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4 +H2O+CO2 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

Question 9

Copy and complete the following table:

Column 1

Substance reacted with acid

Column 2

Dilute or concentrated acid

Column 3

Gas

   

Hydrogen

   

Carbon dioxide

   

Only chlorine

Solution 9

Column 1

Substance reacted with acid

Column 2

Dilute or concentrated acid

Column 3

Gas

Substance reacted with acid

Dilute or concentrated sulphuric acid

Gas

Zinc

Dilute sulphuric acid

Hydrogen

Calcium carbonate

Concentrated sulphuric acid

Carbon dioxide

Bleaching power CaOCl2

Dilute sulphuric acid

only chlorine

 

Question 10

Following are the typical properties of dilute acid complete them by inserting suitable words:

(i) Active metal + Acid ⟶…………. + …………….

(ii) Base + Acid ⟶ ……….. + ………….

(iii) Carbonate/hydrogen carbonate + Acid ⟶ ……….+ ………….+……….

(iv) Sulphite/hydrogen sulphite + Acid ⟶ ………..+………….+………..

(v) Sulphite + Acid ⟶ ……….. +………….

Solution 10

(i) Active metal + Acid ⟶ Metal sulphate + Hydrogen

(ii) Base + Acid ⟶ Salt + Water

(iii) Carbonate/hydrogen carbonate + Acid ⟶ Salt + Water + Carbon dioxide

(iv) Sulphite/hydrogen sulphite + Acid ⟶ Salt + Water + Sulphur dioxide

(v) Sulphite + Acid ⟶ Salt + Hydrogen sulphide

Question 11(a)

Which property of sulphuric acid accounts for its use as a dehydrating agent?

Solution 11(a)

Sulphuric acid is powerful dehydrating agent on account of its strong affinity towards water.

Question 11(b)

Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each to illustrate the above mentioned properties of sulphuric acid.

Solution 11(b)

Concentrated sulphuric acid as

 i. Oxidising agent:

 The oxidising property of conc. sulphuric acid its due to the fact that on thermal decomposition, it yeilds nacent oxygen [O].

 H2SO4 H2O + SO2 + [O] 

 ii. Non-volatile acid:

 conc. sulphuric acid has high boiling point (338°C) that why it is said to be a non volitile compound, therefore it is used for preparing volatile acids like hydrochloric acids, nitric acids from there salts by double decomposition

  H2SO4 + NaCl NaHSO4 + HCl

Question 12

Some properties of sulphuric acid are listed below. Choose the property A, B, C or D which is responsible for the reactions (i) to (v). Some properties may be repeated:

A. Acid

B. Dehydrating agent

C. Non-volatile acid

D. Oxidising agent

(i) C12H22O11 +nH2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid12C + 11H2O + nH2SO4

(ii) S + 2H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid3SO2 +2H2O

(iii) NaCl +H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNaHSO4 + HCl

(iv) CuO + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidCuSO4 +H2O

(v) Na2CO3 + H2SO4 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric AcidNa2SO4 + H2O +CO2

Solution 12

(i) B

(ii) D

(iii) C

(iv) A

(v) A

Question 13

(a) Name the acid formed when sulphur dioxide dissolves in water.

(b) Name the gas released when sodium carbonate is added to a solution of sulphur dioxide.

Solution 13

(a) The acid formed when sulphur dioxide dissolves in water is sulphurous acid.

(b) Carbondioxide gas is released when sodium carbonate is added to solution of sulphur dioxide.

Question 2008
  1. Dilute sulphuric acid will produce a white precipitate when added to a solution of :

 i. Copper nitrate

 ii. Zinc nitrate

 iii. Lead nitrate

 iv. Sodium nitrate

  1. Identify the following substance: Liquid E can be dehydrated to produce ethene.

c. Copy and complete the following table relating to an important industrial process and its final output.

Name of process

Inputs

Catalyst

Equation for catalyzed reaction output

Contact process

Sulphur dioxide + oxygen

 

 

 

  1. Making use only of substances given : dil. sulphuric acid, sodium carbonate, zinc, sodium. sulphite, lead, calcium carbonate : Give equations for the reactions by which you could obtain :

 i. hydrogen

 ii. sulphur dioxide

 iii. carbon dioxide

 iv. zinc carbonate [2 steps]

  1. What property of conc. H2SO4 :

 i. is used in the action when sugar turns black in its presence.

 ii. allows it to be used in the preparation of HCl and HNO3 acids.

f. Write the equations for :

 i. dil. H2SO4 and barium chloride

 ii. dil. H2SO4 and sodium sulphuide

Solution 2008

a. (C) Lead nitrate

b. Liquid E is Ethanol.

c. 

Name of process

Inputs

Catalyst

Equation for catalyzed reaction output

 

 

output

Contact process

Sulphur dioxide + oxygen

Platinum or V2O5

2SO2 + O2  2SO3

Sulphuric acid

d.  

 i. Zn + dil. H2SO4 ZnSO4 + H2 

 ii. Na2CO3 + dil. H2SO4 Na2SO4 + H2O + CO2

 iii. Pb(NO3) + dil. H2SO4 PbSO4  + 2HNO3

 iv. Zn + dil. H2SO4 ZnSO4 + H2

ZnSO4 + Na2CO3 ZnCO3 + Na2SO4

e.  

 i. The property of concentrated sulphuric acid which allows it to be used in is used in the action when sugar turns black in its presence is its dehydrating property. 

 ii. The property of concentrated sulphuric acid which allows it to be used in the preparation of hydrogen chloride and nitric acid is its non-volatility.

H2SO4 + BaCl2   BaSO4 + 2HCl

Question 2009

a. Name the gas evolved [formula is not acceptable]. The gas that can be oxidised to sulphur.

Solution 2009

Hydrogen Chloride

Question 2010

a. Give the equation for :

 i. Heat on sulphur with conc. sulphuric acid

 ii. Reaction of - sugar with conc. sulphuric acid.

b. Give a balanced equation for the conversion of zinc oxide to zinc sulphate.

c. Select the correct answer from A, B, C.

A. Sodium hydroxide solution

B. A weak acid

C. Dilute sulphuric acid.

The solution which liberates sulphur dioxide gas, from sodium sulphite.

Solution 2010

a.  

 i. S + H2SO4 3SO2 +2H2O.

 ii. C12H22O11  + Conc. H2SO4 6C + 6H2O

b. ZnO + H2SO4 ZnSO4 + H2O. 

c. C) Dilute sulphuric acid. 

Question 2011

a. State your observation when - Sugar crystals are added to a hard glass test tube containing conc. sulphuric acid.

b. Choose the correct answer from the choices - The gas evolved when dil. sulphuric acid reacts with iron sulphide.

 i. Hydrogen sulphide

 ii. Sulphur dioxide

 iii. Sulphur trioxide

 iv. Vapour of sulphuric acid

c. Give a balanced equation for :

 i. Dilute sulphuric acid is poured over sodium sulphite.

 ii. Manufacture of sulphuric acid by the - contact process.

d. State the property of sulphuric acid shown by the reaction of conc. sulphuric acid when heated with

 i. potassium nitrate

 ii. carbons

Solution 2011

a. Charring of sugar takes place. Sulphuric acid dehydrates sugar leaving behind carbon which is black in colour.

b. i. Hydrogen sulphide

c. i. Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

ii.

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

d. 

 i. Non-volatile nature

 ii. as an oxidising agent

Question 2012

a. Name - The gas produced on reaction of dilute sulphuric acid with a metallic sulphide.

b. Some properties of sulphuric acid are listed below. Choose the role played by sulphuric acid as A, B, C or D which is responsible for the reactions (i) to (v). Some role/s may be repeated.

 1. Dilute acid

 2 Dehydrating agent

 3. Non-volatile acid

 4. Oxidising agent

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid 

c. Give balanced equation for the reaction : Zinc sulphide and dilute sulphuric acid.

Solution 2012

a. Hydrogen Sulphide (H2S).

b. 

 i. (B) Dehydrating agent

 ii. (D) Oxidising agent

 iii. (C) Non-volatile acid

 iv. (A) Dilute acid

 v. (D) Oxidising agent

c. ZnS + dil.H2SO4 ZnSO4 + H2S

Question 2013

a. State one appropriate observation for : Conc. H2SO4 is added to a crystal of hydrated copper sulphate.

b. In the given equation - S + 2H2SO4 3SO2 + 2H2O :

 Identify the role played by conc. H2SO4.

 i. Non-volatile acid

 ii. Oxidising agent

 iii. Dehydrating agent

 iv. None of the above

c. Give a balanced equation for : Dehydration of concentrated sulphuric acid with sugar crystals.

d. Identify the substance underlined : A dilute mineral acid which forms a white precipitate when treated with barium chloride solution.

Solution 2013

a. when Conc. H2SO4 is added to a crystal of hydrated copper sulphate,it removes water of crystalisation from salt.

b. ii. Oxidising agent 

c. C12H22O11 + Conc. H2SO4 6C + 6H2O

d. Sulphuric acid (H2SO4)

Question 2014

a. Write balanced equations for the following : Action of concentrated sulphuric acid on carbon.

b. Distinguish between the following pairs of compounds using the test given within brackets. Dilute sulphuric acid and dilute hydrochloric acid [using barium chloride solution].

c. State the conditions required for the following reactions to take place : The conversion of sulphur dioxide to sulphur trioxde.

d. Give one equation each to show the following properties of sulphuric acid :

 i. Dehydrating property

 ii. Acidic nature

 iii. As a non-volatile acids

Solution 2014

a. C + H2SO4 CO2 + 2H2O + 2SO2.

b. Sulphuric acid precipitates the insoluble sulphate of barium from the solution of barium chloride.

BaCl2 + H2SO4 BaSO4 + 2HCl

Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.

c. Two conditions for the conversion of sulphur dioxide to sulphur trioxide is as follows: 

Temperature: 450-500° C Catalyst: V2O5

Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid 

d.  

 i. Dehydrating property of sulphuric acid:

H2SO4 has a great affinity for water, and therefore, it acts as a dehydrating agent. 

 Selina Solutions Icse Class 10 Chemistry Chapter - Study Of Compounds D Sulphuric Acid

 ii. Acidic nature of sulphuric acid:

 It acts as a strong dibasic acid.

 H2SO4 2Hi+ + SO42-

 It reacts with metals, metal oxides, metal hydroxides, carbonates etc. to form metallic sulphates and hydrogen at ordinary temperature.

 Mg + H2SO4 MgSO4 + H2 

 CuO + H2SO4 CuSO4 + H2O

 2NaOH + H2SO4 Na2SO4 + 2H2O

 ZnCO3 + H2SO4 ZnSO4 + H2O + CO2 

 iii. As a non-volatile acid:  

It has a high boiling point, so it is used to prepare volatile acids such as HCl, HNO3 and acetic acid from their salts.

NaCl + H2SO4 NaHSO4 + HCl

NaNO3 + H2SO4 NaHSO4 + HNO3

CH3COONa + H2SO4 NaHSO4  + CH3COOH

Question 2015

(a) In the manufacture of sulphuric acid by contact process, give the equations for the conversion of sulphur trioxide to sulphuric acid.

(b) Give equations for the action of sulphuric acid on

(i) Potassium hydrogen carbonate

(ii) Sulphur

(c) Identify the acid in each case.

(i) Acid which produces sugar charcoal from sugar

(ii) Acid on mixing with lead nitrate solution produces white ppt. which is insoluble even on heating

Solution 2015

(a) In the contact process for the manufacture of sulphuric acid, the equations for the conversion of sulphur trioxide to sulphuric acid are

 SO3 + H2SO4 H2S2O7

  (oleum or pyrosulphuric acid)

 

 H2S2O7 + H2O 2H2SO4

(b)  

(i) Action of sulphuric acid on potassium hydrogen carbonate

 2KHCO3+ H2SO4 K2SO4+ 2H2O + 2CO2 

(ii) Action of sulphuric acid on sulphur

 S + 2H2SO4 3SO2 + 2H2O

(c)  

(i) Concentrated sulphuric acid

(ii) Concentrated sulphuric acid