RD SHARMA Solutions for Class 9 Maths Chapter 13 - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise Ex. 13.1

Question 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 3
The angles of quadrilateral are in the ratio 3: 5: 9: 13, Find all the angles of the quadrilateral.
Solution 3
Let the common ratio between the angles is x. So, the angles will be 3x, 5x, 9x and 13x respectively.
Since the sum of all interior angles of a quadrilateral is 360o.
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals 3x + 5x + 9x + 13x = 360o

30x = 360o
    x = 12o
Hence, the angles are
3x = 3 Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals 12 = 36o
5x = 5 Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals 12 = 60o
9x = 9 Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals 12 = 108o
13x = 13 Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals 12 = 156o

Question 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals


Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise Ex. 13.2

Question 1

Two opposite angles of a parallelogram are (3x - 2)° and (50 - x)°. Find the measure of each of the parallelogram.

Solution 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 2

If an angle of a parallelogram is two-third of its adjacent angle, find the angles of the parallelogram.

Solution 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 3

Find the measure of all the angles of a parallelogram, if one angle is 24o less than twice the smallest angle.

Solution 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 4

The perimeter of a parallelogram is 22 cm. If the longer side measures 6.5 cm what is the measure of the shorter side?

Solution 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 5

In a parallelogram ABCD, D = 135°, determine the measures of A and B.

Solution 5

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 6

ABCD is a parallelogram in which A = 70. Compute B, C and D.

Solution 6

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 7

In fig., ABCD is a parallelogram in which DAB = 75° and DBC = 60°. Compute CDB and ADB.

 

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

 




Solution 7

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 8

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 8

i. F

ii. T

iii. F

iv. F

v. T

vi. F

vii. F

viii. T

Question 9

In fig., ABCD is a parallelogram in which A = 60°. If the bisectors of A and b meet at P, prove that AD = DP, PC = BC and DC = 2AD.

 

 



Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 9

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 10

In fig., ABCD is a parallelogram and E is the mid-point of side BC. IF DE and AB when produced meet at F, prove that AF = 2AB.

 

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

 

 




Solution 10

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise Ex. 13.3

Question 1

In a parallelogram ABCD, determine sum of angles C and D.

Solution 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsC and Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsD are cosecutive interior angles on the same side of the transversal CD. Therefore, 

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsC + Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsD = 180o

Question 2

In a parallelogram ABCD, if B = 135°, determine the measures of its other angles.

Solution 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 3

ABCD is a square. AC and BD intersect at O. State the measure of Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsAOB.

Solution 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Since, diagonals of a square bisect each other at right angle. Therefore, Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsAOB = 90o

Question 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 5

The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.

Solution 5

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 6

P and Q are the points of trisection of the diagonal BD of a parallelogram ABCD. Prove that CQ is parallel to AP. Prove also that AC bisects PQ.

Solution 6

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 7

ABCD is a square E, F, G and H are points on AB, BC, CD and DA respectively, such that AE = BF = CG = DH. Prove that EFGH is square.

Solution 7

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 8

ABCD is a rhombus, EABF is a straight line such that EA = AB = BF. Prove that ED and FC when produced meet at right angles.

Solution 8

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 9

ABCD is a parallelogram, AD is produced to E so that DE = DC and EC produced meets AB produced in F. Prove that BF = BC.

Solution 9

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise Ex. 13.4

Question 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 4

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 5

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 5

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 6

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 6

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 7

In fig., triangle ABC is right-angled at B. Give that AB = 9 cm, AC = 15 cm and D, E are the mid-points of the sides AB and AC respectively, calculate

(i) The length of BC

(ii) The area of Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsADE.

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 7

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 8

In fig., M, N, and P are the mid-points of AB, AC and BC respectively. If MN = 3 cm, Np = 3.5 cm and MP = 2.5 cm, Calculate BC, AB and AC.

 

 



Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 8

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 9

In fig., AB = AC and CP  BA and AP is the bisector of exterior CAD of ΔABC. Prove that (i) PAC = BCA (ii) ABCP is a parallelogram.

 


Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 9

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 10

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 10

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 11

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 11

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 12
Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other.
Solution 12
                                           Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Let ABCD is a quadrilateral in which P, Q, R and S are mid-points of sides AB, BC, CD and DA respectively.
Join PQ, QR, RS, SP and BD.
In Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsABD, S and P are mid points of AD and AB respectively.
So, By using mid-point theorem, we can say that
SP || BD and SP =  Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals BD             ... (1)  
Similarly in Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - QuadrilateralsBCD
QR || BD and QR = Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals BD               ... (2)
From equations (1) and (2), we have
SP || QR and SP = QR  
As in quadrilateral SPQR one pair of opposite sides are equal and parallel to
each other.
So, SPQR is a parallelogram.
Since, diagonals of a parallelogram bisect each other.
Hence, PR and QS bisect each other.

Question 13

Fill in the blanks to make the following statements correct:

(i) The triangle formed by joining the mid-points of the sides of an isosceles traingle is ______.

(ii) The triangle formed by joining the mid-points of the sides of a right triangle is ______ .

(iii) The figure formed by joining the mid-points of consecutive sides of a quadrilateral is ______ .

Solution 13

(i) isosceles

(ii) right triangle

(iii) parallelogram

Question 14

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 14

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 15

In fig., BE  AC. AD is any line from A to BC interesting BE in H. P, Q and R are respectively the mid-points of AH, AB and BC. Prove that PQR = 90°.



Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 15

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 16

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 16

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 17

In fig., ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ = (1/4)AC. If PQ produced meets BC at R, prove that R is a mid-point of BC.

 

 



Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 17

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 18

In fig., ABCD and PQRC are rectangle and Q is the mid-point of AC. Prove that 

i. DP = PC ii. PR = (1/2) AC

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 18

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 19

ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC and G, P and H respectively. Prove that GP = PH.

Solution 19

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals
Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 20

BM and CN are perpendiculars to a line passing through the vertex A of a triangle ABC. If L is the mid-point of BC, prove that LM = LN.

Solution 20

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise 13.70

Question 1

The opposite sides of a quadrilateral have 

(a) no common point

(b) one common point

(c) two common points

(d) infinitely many common points

Solution 1

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

ABCD is a Quadrilateral.

The opposite sides AB and DC, AD and BC have no common point.

Hence, correct option is (a).

Question 2

The consecutive sides of a quadrilateral have

(a) no common point

(b) one common point

(c) two common points

(d) infinitely many common points

Solution 2

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Consecutive sides of a Quadrilateral ABCD are

AB and BC,

BC and CD,

CD and AD,

AD and AB,

which have only one point in common

i.e the joint point of their ends.

Hence, correct option is (b).

Chapter 13 - Quadrilaterals Exercise 13.71

Question 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

 

Solution 3

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 4

Which of the following quadrilateral is not a rhombus?

(a) All four sides are equal

(b) Diagonals bisect each other

(c) Diagonals bisect opposite angles

(d) One angle between the diagonals is 60°

Solution 4

For a rhombus, the angle between the diagonals is 90° and not 60°.

Hence, correct option is (d).

Question 5

Diagonals necessarily bisect opposite angles in a

(a) rectangle

(b) parallelogram

(c) isosceles trapezium

(d) square

Solution 5

Diagonals necessarily bisect opposite angles in a square.

Hence, correct option is (d).

Question 6

The two diagonals are equal in a 

(a) parallelogram

(b) rhombus

(c) rectangle

(d) trapezium

Solution 6

The two diagonals are equal in a rectangle (property).

Hence, correct option is (c).

Question 7

We get a rhombus by joining the mid-points of the sides of a 

(a) parallelogram

(b) rhombus

(c) rectangle

(d) triangle

Solution 7

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 8

The bisectors of any two adjacent angles of a parallelogram intersect at

(a) 30°

(b) 45°

(c) 60°

(d) 90°

Solution 8

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 9

The bisectors of the angle of a parallelogram enclose a

(a) parallelogram

(b) rhombus

(c) rectangle

(d) square

Solution 9

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

AR, BR, CP, DP are the bisectors of angles of parallelogram.

Because two bisectors of adjacent angles make 90° between them So  PQRS is a Rectangle

Because DP and BR are acute angle bisectors so the distance between them PQ < PS (The distance between other two bisectors)

So PQ ≠ PS (So PQRS  is not a square, but only a rectangle)

Hence, correct option is (c).

Question 10

The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a 

(a) parallelogram

(b) rectangle

(c) square

(d) rhombus

Solution 10

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 11

The figure formed by joining the mid-points of the adjacent sides of a rectangle is a

(a) square

(b) rhombus

(c) trapezium

(d) none of these

Solution 11

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 12

The figure formed by joining the mid-points of the adjacent sides of a rhombus is a

(a) square

(b) rectangle

(c) trapezium

(d) none of these

Solution 12

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 13

The figure formed by joining the mid-points of the adjacent sides of a square is a

(a) rhombus

(b) square

(c) rectangle

(d) parallelogram

Solution 13

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 14

The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a

(a) rectangle

(b) parallelogram

(c) rhombus

(d) square

Solution 14

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 15

If one angle of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is

(a) 176°

(b) 68°

(c) 112°

(d) 102°

Solution 15

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 16

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 16

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals


Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 17

ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCD respectively, then EF =

(a) AE

(b) BE

(c) CE

(d) DE

Solution 17

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise 13.72

Question 18

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 18

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 19

If an angle of  a parallelogram is is two-third of its adjacent angle, the smallest angle of the parallelogram is

(a) 108°

(b) 54°

(c) 72°

(d) 81°

Solution 19

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 20

If the degree measures of the angles of quadrilateral are 4x, 7x, 9x and 10x, what is the sum of the measures of the smallest angle and largest angle?

(a) 140°

(b) 150°

(c) 168°

(d) 180°

Solution 20

Sum of all angles of a Quadrilateral = 360°

4x + 7x + 9x + 10x = 360°

30x = 360°

x = 12°

So, sum of smallest and largest angle,

i.e. 4x + 10x = 14x = 14 × 12 = 168°

Hence, correct option is (c).

Question 21

If the diagonals of a rhombus are 18 cm and 24 cm respectively, then its side is equal to

(a) 16 cm

(b) 15 cm

(c) 20 cm

(d) 17 cm

Solution 21

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 22

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 22

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 23

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 23

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 24

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 24

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 25

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 25

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 26

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 26

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 30

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 30

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 27

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 27

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 28

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 28

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 29

In ΔABC, E is the mid-point of median AD such that BE produced meets AC at F. If AC = 10.5 cm, then AF =

(a) 3 cm

(b) 3.5 cm

(c) 2.5 cm

(d) 5 cm

Solution 29

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Chapter 13 - Quadrilaterals Exercise 13.73

Question 31

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 31

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Question 32

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Solution 32

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals

Rd-sharma Solutions Cbse Class 9 Mathematics Chapter - Quadrilaterals