NCERT Solutions for Class 10 Maths Chapter 8 - Introduction to Trigonometry
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Chapter 8 - Introduction to Trigonometry Exercise Ex. 8.1
In ABC by applying Pythagoras theorem
AC2 = AB2 + BC2
= (24)2 + (7)2
= 576 + 49
AC = = 25 cm
Since A and B are acute angles, then C is a right angle.
cos A = cos B .... given
AC/AB = BC/AB
AC = BC
B =A .... angles opposite to equal sides are equal in length.
Chapter 8 - Introduction to Trigonometry Exercise Ex. 8.2
Chapter 8 - Introduction to Trigonometry Exercise Ex. 8.3
tan 2A = cot (A - 18)
cot (90 - 2A) = cot (A -18)
90 - 2A = A - 18
108 = 3A
A = 36
tan A = cot B
tan A = tan (90 - B)
A = 90 - B
A + B = 90
Sec 4A = cosec (A - 20)
Cosec (90 - 4A) = cosec (A - 20)
90 - 4A = A - 20
110 = 5A
A = 22
sin 67 + cos 75
= sin (90 - 23) + cos (90 - 15)
= cos 23 + sin 15
Chapter 8 - Introduction to Trigonometry Exercise Ex. 8.4
(i) 9sec2A - 9tan2A
= 9(sec2A - tan2A)
= 9 (1) (as sec2A - tan2A = 1)
Hence alternative (B) is correct.
(ii) (1 + tanθ + secθ) (1 + cotθ - cosecθ)
Hence alternative (C) is correct.
(iii) (secA + tanA) (1 - sinA)
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Other Chapters for CBSE Class 10 MathematicsChapter 1- Real Numbers Chapter 2- Polynomials Chapter 3- Pairs of Linear Equations in Two Variables Chapter 4- Quadratic Equations Chapter 5- Arithmetic Progressions Chapter 6- Triangles Chapter 7- Coordinate Geometry Chapter 9- Some Applications of Trigonometry Chapter 10- Circles Chapter 11- Constructions Chapter 12- Areas Related to Circles Chapter 13- Surface Areas and Volumes Chapter 14- Statistics Chapter 15- Probability
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