two numbers are such that three times the first added to four times the second is 96 and the excess of four times the first over three times the second is three find the number

Asked by Gangrademohini | 1st Jan, 2020, 10:58: PM

Expert Answer:

Let  and y be the two numbers
As per the question,
3x+4y=96 ... (i) and
4x=3y+3
i.e. 4x-3y=3 ... (ii)
Multiplying (i) by 3 and (ii) by 4, we have
9x+12y=288 ... (iii)
16x-12y=12 ... (iv)
Adding (iii) and (iv), we have
25x=300
i.e. x=12
Substituting x in (i), we get
3(12)+4y=96
4y=96-36=60
Therefore, y=15.

Answered by Renu Varma | 2nd Jan, 2020, 11:09: AM

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