maths

Asked by garuleanushka | 5th Sep, 2020, 10:02: PM

Expert Answer:

Q: Given that HCF(306, 657)  =9, find LCM(306, 657).
 
Solution:
 
We know that,
 
HCF(a, b) × LCM(a, b) = a×b
begin mathsize 16px style LCM left parenthesis straight a comma space straight b right parenthesis equals fraction numerator straight a cross times straight b over denominator HCF left parenthesis straight a comma space straight b right parenthesis end fraction equals space fraction numerator 306 cross times 657 over denominator 9 end fraction equals space 22338 end style

Answered by Yasmeen Khan | 7th Sep, 2020, 12:08: PM