Integral limit0 to1e^x^2dx lies between

Asked by lakkireddysupriya3 | 1st May, 2020, 11:25: AM

Expert Answer:

To find the interval in which integral limit 0 to 1 ex^2 lies between
m left parenthesis b minus a right parenthesis less than integral subscript 0 superscript 1 e to the power of x squared end exponent space d x less than M left parenthesis b minus a right parenthesis space space... space U sin g space p r o p e r t i e s space o f space d e f i n i t e space i n t e g r a l
H e r e comma space m space i s space t h e space m i n i m u m space v a l u e space o f space f left parenthesis x right parenthesis equals e to the power of x squared end exponent space a n d space M space i s space t h e space m a x i m u m space v a l u e
m equals f open parentheses 0 close parentheses equals e to the power of 0 equals 1
M equals f left parenthesis 1 right parenthesis equals e to the power of 1 squared end exponent equals 1
1 left parenthesis 1 minus 0 right parenthesis less than integral subscript 0 superscript 1 e to the power of x squared end exponent d x less than e left parenthesis 1 minus 0 right parenthesis
1 less than integral subscript 0 superscript 1 e to the power of x squared end exponent d x less than e

Answered by Renu Varma | 1st May, 2020, 06:44: PM

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