In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

Total number of balls = S = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green.

Answered by  | 4th Jun, 2014, 03:23: PM