In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
Total number of balls = S = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green.
Answered by | 4th Jun, 2014, 03:23: PM
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