How to find the zeros of x2-2x-8

Asked by vishakhatania | 5th May, 2020, 01:14: PM

Expert Answer:

Given polynomial is P(x)=x2-2x-8
Take P(x)=0
x2-2x-8=0
x2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4 or x=-2

Answered by Renu Varma | 5th May, 2020, 07:08: PM