Find the zeroes of the following quadratic polynomial :

1)4s² -4s+1

2)6x²-3-7x

3)4u²+8u

4)3x²-x-4

Asked by ashleshathakur124 | 15th Oct, 2019, 07:42: PM

Expert Answer:

2)
6x² - 3 - 7x = 0 
6x2 - 7x - 3 = 0
6x2 - 9x + 2x - 3 = 0
3x(2x - 3) + (2x - 3) = 0
(2x - 3)(3x + 1) = 0
2x - 3 = 0 or 3x + 1 = 0
x = 3/2 or x = -1/3

Answered by Sneha shidid | 16th Oct, 2019, 09:36: AM