Can you please answer the question given in the image

Asked by thakuraaishaashraf | 19th May, 2020, 09:38: PM

Expert Answer:

To find the integral of sin2x+cos2x between the limits 3pi/2 and pi
integral subscript straight pi superscript fraction numerator 3 straight pi over denominator 2 end fraction end superscript open parentheses sin squared x plus cos squared x close parentheses d x
equals integral subscript straight pi superscript fraction numerator 3 straight pi over denominator 2 end fraction end superscript d x
equals open square brackets x close square brackets subscript straight pi superscript fraction numerator 3 straight pi over denominator 2 end fraction end superscript
equals fraction numerator 3 straight pi over denominator 2 end fraction minus straight pi
equals straight pi over 2

Answered by Renu Varma | 20th May, 2020, 10:23: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.